3+3=6-3+2:5-2=?

To solve the expression \(3 + 3 = 6 – 3 + 2 \div 5 – 2\), we need to evaluate it step by step, following the order of operations (PEMDAS/BODMAS):

1. **Parentheses/Brackets**: There are no parentheses or brackets to evaluate.
2. **Exponents/Orders**: There are no exponents in this expression.
3. **Multiplication and Division**: From left to right.
– \(2 \div 5\) is evaluated first, which is \(0.4\).

4. **Addition and Subtraction**: From left to right.
– Start with the leftmost addition: \(3 + 3 = 6\).
– Now substitute back into the expression: \(6 – 3 + 0.4 – 2\).
– Evaluate \(6 – 3 = 3\).
– Substitute back: \(3 + 0.4 – 2\).
– Evaluate \(3 + 0.4 = 3.4\).
– Substitute back: \(3.4 – 2\).
– Evaluate \(3.4 – 2 = 1.4\).

Therefore, the result of the expression is \(1.4\).

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